Daily Practice Questions For NEET UG 2026 to score 650+ (DAY 15)

Daily Practice Questions For NEET UG 2026: To help NEET UG 2026 aspirants stay consistent and exam-ready, we bring you Day 15 of the Daily Practice Questions series, specially crafted for students aiming to score 650+. This set focuses on concept-based and exam-oriented MCQs that mirror the NEET pattern, making it an essential part of your daily revision strategy.

PHYSICS

Q.1. A projectile is fired from the ground with an initial speed $v_0$ making an angle $\theta$ with the horizontal. Air resistance is negligible. At a point in its trajectory where its velocity makes an angle ${45}^{\circ }$ with the horizontal, its speed is found to be ${\displaystyle \frac{v_0}{\sqrt{2}}}$. What is the initial angle of projection $\theta$?

A. ${45}^{\circ }$

B. ${60}^{\circ }$

C. ${75}^{\circ }$

D. ${30}^{\circ }$

Q.2. In a Young’s double-slit experiment, monochromatic light of wavelength λ produces an interference pattern on a screen placed at distance $D$ from the slits, which are separated by distance $d$. If the entire apparatus is immersed in a liquid of refractive index $\mu$, what happens to the fringe width $\beta$, and why?

A. β decreases by a factor of $\mu$μ because wavelength becomes ${\displaystyle \frac{\lambda }{\mu }}$ in the medium

B. β becomes zero because interference cannot occur in a medium

C. β remains the same because the slit separation and screen distance are unchanged

D. β increases by a factor of $\mu$μ because wavelength in the medium is $\mu \lambda$μλ

Q.3. In electrostatics, a conducting solid sphere is given a charge +Q. A small uncharged conducting hollow shell is then brought near it without touching. Which statement best describes the final distribution of charges once they are brought in contact and then separated far apart?

A. All charge remains on the initially charged sphere because conductors retain original charges

B. Both objects end up with charge +Q/2 because charge distributes equally by symmetry

C. The smaller object gets almost all the charge because it is closer to the source of charge

D. The charges rearrange to make potentials equal; the final distribution depends on their radii

Q.4. A concave mirror forms an image of a real object placed beyond its center of curvature. Suppose the mirror is now placed in water $(\mu >1)$ while the object and image remain in water. How are the mirror formula ${\displaystyle \frac{1}{f}}={\displaystyle \frac{1}{v}}+{\displaystyle \frac{1}{u}}$ and focal length $f$ affected?

A. The mirror formula remains valid with the same focal length f  because reflection is independent of medium

B. The focal length changes to $f\mathrm{/}\mu$ because speed of light is lower in water

C. The mirror formula fails because refraction at the water surface dominates over reflection

D. The focal length changes sign because water behaves like a lens in front of the mirror

Q.5. A body of mass 2kg is acted upon by a constant force of 10 N. What is its acceleration?

A. 5m s-2

B. $10{\text{m s}}^{-2}$

C. $20{\text{m s}}^{-2}$

D. $2{\text{m s}}^{-2}$

Read Also: NEET UG Daily Practice Questions For 2026 to score 650+ (DAY 14)

CHEMISTRY

Q.6. For the reaction $2{\text{NO}}_2(g)\rightleftharpoons {\text{N}}_2{\text{O}}_4(g)$, which change will shift the equilibrium towards ${\text{N}}_2{\text{O}}_4(g)$ according to Le Chatelier’s principle?

A. Compressing the mixture at constant temperature

B. Increasing the temperature for an exothermic forward reaction

C. Adding an inert gas at constant volume

D. Decreasing the pressure at constant temperature

Q.7. Which of the following aqueous solutions has the highest boiling point, assuming complete dissociation where applicable?

A. $0.1\text{mol}{\text{kg}}^{-1}$

B. $0.1\text{mol}{\text{kg}}^{-1}$${\text{CaCl}}_2$

C. $0.1\text{mol}{\text{kg}}^{-1}$NaCl

D. $0.1\text{mol}{\text{kg}}^{-1}$ glucose

Q.8. Which of the following statements about the order of a reaction is correct?

A. Order of a reaction is always equal to the molecularity

B. Order of a reaction can be fractional or zero

C. Order of a reaction is determined by the balanced stoichiometric equation alone

D. Order of a reaction can never change with temperature

Q.9. In the electrolysis of molten $\text{NaCl}$, which species are discharged at the electrodes?

A. Na+ at cathode and ${\text{O}}^{2-}$ at anode

B. H+ at cathode and ${\text{Cl}}^{-}$at anode

C. Cl− at cathode and ${\text{Na}}^{+}$ at anode

D. Na+ at cathode and ${\text{Cl}}^{-}$ at anode

Q.10. Which of the following statements about adsorption is correct?

A. Chemisorption is always reversible and occurs at very low temperatures

B. Chemisorption is usually specific and may involve activation energy

C. Physisorption always increases with increase in temperature

D. Physisorption involves the formation of chemical bonds between adsorbate and adsorbent

BIOLOGY

Q.11. The hydrogen bond present between Adenine and Thymine is:

A. One
B. Two
C. Three
D. Four

Q.12. Which component forms the backbone of DNA?

A. Nitrogenous bases
B. Hydrogen bonds
C. Sugar and phosphate
D. Ribose sugar

Q.13.Which part of bacteriophage helps in attachment to the host?

A. Head
B. Collar
C. Tail fibers
D. Capsomere

Q.14. Shape of bacteriophage head is:

A. Helical
B. Cuboidal
C. Icosahedral
D. Spherical

Q.15. Maximum reabsorption of glucose occurs in:

A. DCT
B. Loop of Henle
C. PCT
D. Collecting duct

Regular practice is the key to success in NEET UG, and solving daily MCQs helps build speed, confidence, and conceptual clarity. Make sure to attempt all questions, analyze your mistakes, and revise weak areas. Stay connected with us for upcoming daily practice sets and take one step closer to your dream medical college.

Read Also: Most Important Biology Diagram For NEET UG 2026 to Score 650+

ANSWERS & EXPLANATIONS

Ans.1. B. 60∘. At the point where the velocity makes ${45}^{\circ }$with the horizontal, we must have $v_x=v_y$ Since $v_x$vx is constant and equals $v_0\cos \theta$ let this common value be $v_x$. Then the speed at that instant is $v=\sqrt{v_x^2+v_y^2}=\sqrt{2}{v}_x$.

Ans.2. A. β decreases by a factor of $\mu$ because the wavelength becomes ${\displaystyle \frac{\lambda }{\mu }}$ in the medium. From the relation $\beta ={\displaystyle \frac{\lambda D}{d}}$ , and knowing that the speed of light decreases in a medium with refractive index $\mu$μ while frequency remains constant, we find ${\lambda }^{\mathrm{\prime }}={\displaystyle \frac{\lambda }{\mu }}$ Hence ${\beta }^{\mathrm{\prime }}={\displaystyle \frac{{\lambda }^{\mathrm{\prime }}D}{d}}={\displaystyle \frac{\lambda D}{\mu d}}$.

Ans.3. D.  charges rearrange so that the final potentials become equal, and the actual final charges depend on their radii (and thus capacitances). For isolated conducting spheres, the potential is $V={\displaystyle \frac{1}{4\pi {\epsilon }_0}}{\displaystyle \frac{Q}{R}}$ , where $R$ is the radius. When two such spheres are connected (by contact or a wire), charges flow until both reach the same potential. 

Ans.4. A. The mirror formula remains valid with unchanged focal length f. Mirrors work by reflection off a surface, where the law of reflection ∠i=∠r does not depend on the refractive index of the medium. 

Ans.5. A. $5{\text{m s}}^{-2}$. Newton’s second law states $F=ma$ 

Ans.6. A. Compressing the mixture at constant temperature. Compression reduces volume, thereby increasing the partial pressures of all gases. Because the equilibrium involves 2 moles of reactant gas and 1 mole of product gas, the system can minimize the effect of this pressure increase by shifting to the side with fewer gas molecules, i.e., towards ${\text{N}}_2{\text{O}}_4$.

Ans.7. B. $0.1\text{mol}{\text{kg}}^{-1}$CaCl2 . Using the relation $\mathrm{\Delta }{T}_b=i{K}_{b}m$, we see that for equal $m$m and the same solvent, the solution with the largest $i$ will have the highest boiling point. 

Ans.8. B.  Order of a reaction can be fractional or zero. This highlights the experimental nature of reaction order. Many reactions show non-integer orders because of complex mechanisms, surface adsorption, or chain processes. Zero-order reactions, where rate is independent of reactant concentration, occur in situations like saturated catalyst surfaces or photochemically controlled decompositions.

Ans.9. D. Na+ at cathode and ${\text{Cl}}^{-}$ at anode. In molten $\text{NaCl}$, ${\text{Na}}^{+}$ ions are reduced at the cathode to produce metallic sodium, and ${\text{Cl}}^{-}$ ions are oxidized at the anode to release chlorine gas. This understanding is key to remembering the basic principles of electrolysis and the nature of products formed at each electrode.

Ans. 10. B.  Chemisorption is usually specific and may involve activation energy. Chemisorption involves the formation of chemical bonds between adsorbate molecules and the surface of the adsorbent. This process often requires the adsorbate to overcome an energy barrier (activation energy) to react with surface sites, making it more likely at higher temperatures compared to physisorption. Additionally, chemisorption is highly specific because it depends on the chemical nature and reactivity of both the adsorbent and the adsorbate, such as hydrogen chemisorbing on nickel surfaces during catalytic reactions.

Ans.11. B

Ans.12. C

Ans.13. C.

Ans.14. C.

Ans.15. C