NEET UG 2026 Daily Practice Paper Day 45: Day 45 and the finish line is getting closer than ever! This is not just another practice paper- it’s a chance to sharpen your instincts, boost your confidence, and remind yourself how far you’ve already come. Every question you attempt today is one step closer to your dream medical college. So take a deep breath, trust your preparation, and dive in with full energy, because this is your moment to rise and shine!
Q.1. In a closed container, liquid water and its vapor are in equilibrium at a constant temperature. Which change will increase the equilibrium vapor pressure of water in the container?
A. Decreasing the volume of the container without changing temperature
B. Raising the temperature of the container while keeping it closed
C. Adding a small amount of common salt to the water
D. Adding more liquid water to the container
Q.2. An object is projected horizontally from the top of a tall cliff with speed . Air resistance is negligible. Which statement about its motion just before hitting the ground is correct?
A. Its horizontal velocity is and vertical velocity is nonzero
B. Its horizontal and vertical velocities are both equal to
C. Its horizontal velocity is zero and vertical velocity is maximum
D. Its velocity makes a constant angle with the horizontal throughout the motion
Q.3. A long straight conductor carries a steady current . At point P, located at a perpendicular distance from the wire, the magnetic field is . If the current is doubled and the distance is halved, what will be the new magnetic field at point P?
A. It becomes
B. It becomes
C. It remains
D. It becomes
Q.4. A gas sample follows the ideal gas equation. If its pressure is doubled and absolute temperature is tripled while the amount of gas remains constant, what happens to its volume?
A. It becomes three-halves of the original volume
B. It becomes two-thirds of the original volume
C. It becomes six times the original volume
D. It becomes one-sixth of the original volume
Q.5. A student wants to increase the yield of a reversible exothermic reaction carried out in a closed container. Which change will most effectively increase the equilibrium concentration of ?
A. Adding an inert gas at constant volume
B. Increasing the temperature of the system
C. Adding a catalyst to the reaction mixture
D. Decreasing the temperature of the system
Q.6. An action potential in a neuron is characterized by a rapid depolarization phase. What primarily causes this depolarization?
A. Influx of ions through voltage-gated channels
B. Efflux of ions through voltage-gated channels
C. Influx of ions through voltage-gated channels at the axon terminal
D. Efflux of ions through ligand-gated channels
Q.7. Which experimental setup best demonstrates osmosis across a semipermeable membrane?
A. A concentrated sucrose solution separated from pure water by a semipermeable membrane that allows only water to pass
B. A dilute sodium chloride solution separated from a more concentrated sodium chloride solution by a membrane that allows only and ions to pass
C. Two gas samples at equal pressure separated by a rigid, impermeable barrier
D. Two solutions of equal water potential separated by a fully permeable membrane
Q.8. In a patient with uncontrolled diabetes mellitus, which observation in urine analysis most directly indicates poor glucose regulation?
A. Presence of proteins in urine
B. Presence of ketone bodies in urine
C. Presence of glucose in urine
D. Presence of bile pigments in urine
Q.9. Which cellular structure is directly responsible for packaging and modifying proteins for secretion outside the cell?
A. Rough endoplasmic reticulum
B. Smooth endoplasmic reticulum
C. Golgi apparatus
D. Lysosome
Q.10. Which statement about enzyme inhibition best distinguishes competitive from non-competitive inhibition?
A. Competitive inhibitors can be overcome by sufficiently increasing substrate concentration
B. Competitive inhibitors bind only to the allosteric site, not the active site
C. Competitive inhibitors reduce the maximum velocity of the enzyme without changing
D. Competitive inhibitors form irreversible covalent bonds with the enzyme
Q.11. In an ecosystem, which change would most directly reduce the primary productivity of a grassland over the long term?
A. A long-term decrease in soil nitrogen content due to overgrazing
B. A temporary increase in the population of herbivores
C. Seasonal migration of some bird species out of the area
D. An increase in the number of top carnivores such as wolves
Q.12. Which option correctly relates cardiac output, heart rate, and stroke volume in a healthy adult at rest?
A. Cardiac output equals the product of heart rate and stroke volume
B. Cardiac output equals heart rate divided by stroke volume
C. Cardiac output equals stroke volume divided by heart rate
D. Cardiac output is independent of both heart rate and stroke volume
Q.13. Which evolutionary change in a population most clearly represents directional selection?
A. Dark and light fur color variants in a population are both maintained because each is favored in different microhabitats
B. Over time, only bacteria with very high antibiotic resistance survive in a hospital environment
C. Individuals with intermediate-sized beaks are favored over both very small and very large beaks
D. A population splits into two isolated groups that evolve independently over many generations
Q.14. A gas follows the equation of state , where is a positive constant. For moles of this gas undergoing an isothermal expansion from volume to at temperature , which expression correctly represents the work done by the gas?
A.
B.
C.
D.
Q.15. Two identical thin lenses, each of focal length , are separated by along the common principal axis in air. An object is placed in front of the first lens. What is the net magnification produced by the combination?
A.
B.
C.
D. 2
ANSWERS & EXPLANATIONS
Ans. 1. B. Raising the temperature of the container while keeping it closed. As temperature increases, the average kinetic energy of water molecules increases. More molecules can then overcome intermolecular attractions like hydrogen bonding and move into the gas phase. The higher rate of evaporation leads to a higher equilibrium vapor pressure. This behavior is universal for liquids and is crucial for understanding phenomena such as boiling, where the vapor pressure becomes equal to the external pressure at a specific temperature.
Ans. 2. A. Its horizontal velocity is and vertical velocity is nonzero. Using the equations of motion for free fall, the vertical component is given by for an object falling from height (starting from zero vertical velocity), independent of the horizontal speed. Thus, just before touching the ground, the horizontal component is still while the vertical component has grown to some value determined by the fall height. This illustrates the independence of horizontal and vertical motions in ideal projectile motion.
Ans. 3. A. It becomes 4B. From the relation , we can analyze each change stepwise. First, doubling changes to . Next, halving while keeping the new current fixed doubles the field again because varies inversely with distance. Combining both effects, the net factor is , so the new field is .
Ans. 4. A. It becomes three-halves of the original volume. Because for a fixed amount of ideal gas, you can treat the temperature and pressure changes as scaling factors. Tripling temperature multiplies volume by 3, and doubling pressure divides volume by 2, giving a net factor of .
Ans.5. D. Decreasing the temperature of the system. When the temperature is lowered, heat is effectively removed. In an exothermic equilibrium, this is analogous to removing a product, so the system responds by shifting the equilibrium to the right, producing more B and heat to partially counteract the change. As a result, the equilibrium concentration of B increases. This is why lower temperatures often favor the formation of products in exothermic reactions, although in practice, there is a trade-off between higher yield at low temperatures and faster reaction rates at higher temperatures.
Ans. 6. A. Influx of ions through voltage-gated channels. During the rising phase of an action potential, a stimulus causes some voltage-gated channels to open. Sodium ions, driven by both the concentration gradient and electrical gradient, rush into the neuron, making the inside more positive. This positive feedback further opens more channels, rapidly depolarizing the membrane from around mV toward and sometimes beyond 0 mV.
Ans. 7. A. A concentrated sucrose solution is separated from pure water by a semipermeable membrane that allows only water to pass. In osmosis, water moves from a region of higher water potential to lower water potential through a membrane that does not permit solute passage, generating osmotic pressure and volume changes.
Ans. 8. C. Presence of glucose in urine. In a healthy individual, almost all filtered glucose in the nephron is reabsorbed by the proximal convoluted tubule, so urine is essentially glucose-free. When blood glucose levels exceed the renal threshold (about 180 mg/dL), the glucose transporters become saturated, and excess glucose remains in the filtrate and appears in urine, a condition called glucosuria. This directly reflects hyperglycemia and poor glucose regulation.
Ans. 9. C. Golgi apparatus. After proteins are synthesized on ribosomes of the RER, they are transported in vesicles to the Golgi apparatus. Within the Golgi, proteins undergo further post-translational modifications, including trimming, glycosylation, and sulfation, and are sorted into vesicles that target them either to the plasma membrane for exocytosis, to lysosomes, or to other destinations.
Ans.10. A. Competitive inhibitors can be overcome by sufficiently increasing substrate concentration. In competitive inhibition, substrate and inhibitor compete for access to the active site. If you raise the concentration of substrate, there is a higher probability that substrate, rather than inhibitor, occupies the site at any given time. As substrate concentration becomes very high, the inhibitory effect diminishes, and the same as in the uninhibited reaction can be reached.
Ans .11. A. A long-term decrease in soil nitrogen content due to overgrazing. When overgrazing removes too much plant cover, it promotes soil compaction and erosion and disrupts nutrient cycling. Nitrogen, often present in organic matter, is lost as topsoil is eroded or organic matter decomposes without adequate replacement. As nitrogen stocks decline, plants become nitrogen-limited, restricting their growth and reducing primary productivity year after year. This chronic nutrient limitation is far more damaging to the productive capacity of a grassland than temporary changes in herbivore or bird populations.
Ans. 12. A. Cardiac output equals the product of heart rate and stroke volume. Cardiac output is defined as the volume of blood pumped by each ventricle per minute. Heart rate is measured in beats per minute, and stroke volume is the volume ejected per beat. When you multiply heart rate (beats per minute) by stroke volume (milliliters per beat), the beats cancel, leaving milliliters per minute, which correctly represents the volume pumped per unit time. This relationship underpins how the body adjusts blood flow to meet tissue demands; increases in either heart rate or stroke volume (within physiological limits) raise cardiac output.
Ans. 13. B. Over time, only bacteria with very high antibiotic resistance survive in a hospital environment. In this scenario, the environment consistently favors bacteria at the high-resistance end of the trait spectrum. Over time, the frequency distribution of resistance levels shifts so that high-resistance forms become common and low-resistance forms are eliminated. This kind of shift in the population mean toward one extreme is the hallmark of directional selection. Similar patterns occur when pollution favors darker colored moths or when climate change favors earlier flowering times.
Ans.14. D. . Starting from , we integrate from the initial to the final volume: . This gives a positive work for expansion and negative for compression, matching physical expectations for an isothermal reversible process.
Ans. 15. B. . Detailed application of the thin lens formula to each lens and multiplication of the individual magnifications show the net magnification is approximately 1.5 in magnitude, with an inverted final image.
As you wrap up today’s practice, remember, consistency beats perfection. Every effort you put in right now is building the version of you that will walk confidently into the exam hall. We’re constantly working to bring you the best questions and solutions, so your feedback truly means everything to us; it keeps us motivated to do better for you. If you have any doubts, concerns, or even feel overwhelmed, don’t hesitate to share. We’re always here to support you. Keep going, stay focused, and believe in yourself, you’ve got this!
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