NEET UG 2026 Daily Practice Paper Day 46

NEET UG 2026 Daily Practice Paper Day 46: Day 46 of our Daily Practice Paper series is designed to sharpen your intuition and speed, focusing on high-yield concepts that frequently appear in the competitive landscape. With the vast NCERT syllabus requiring constant reinforcement, today’s set provides a balanced mix of 11th and 12th-standard topics, ensuring that your foundation remains rock-solid.

Q.1. For the ionic compound ${\text{MgCl}}_2$, which of the following statements best explains its relatively high melting point compared to $\text{NaCl}$?

A. ${\text{MgCl}}_2$ forms simple covalent molecules that pack better in the solid state

B. ${\text{MgCl}}_2$ has weaker ionic bonds due to higher charge density of ${\text{Mg}}^{2+}$

C. ${\text{MgCl}}_2$ has metallic bonding in addition to ionic bonding, raising its melting point

D. ${\text{MgCl}}_2$ has stronger ionic bonds because ${\text{Mg}}^{2+}$ has a higher charge than ${\text{Na}}^{+}$

Q.2. A ball is thrown vertically upward with an initial speed of $20{\text{m s}}^{-1}$. Neglecting air resistance and taking $g=10{\text{m s}}^{-2}$, what is the total time for which the ball remains in the air before returning to the thrower’s hand at the same level?

A. 2 $\text{s}$

B. 4 $\text{s}$

C. 3 $\text{s}$

D. 1 $\text{s}$

Q.3. Which of the following best describes the role of ribosomes in a eukaryotic cell?

A. They store genetic information and direct cell activities

B. They synthesize lipids and detoxify drugs

C. They generate ATP through oxidative phosphorylation

D. They synthesize proteins by translating messenger RNA

Q.4. A gas at $300\text{K}$ and $1\text{atm}$ pressure is compressed isothermally to one-third of its initial volume. Assuming ideal behavior, what happens to the pressure and why?

A. Pressure increases slightly but cannot be predicted without Van der Waals constants

B. Pressure remains $1\text{atm}$ because temperature is constant

C. Pressure becomes ${\displaystyle \frac{1}{3}}\text{atm}$ because pressure is inversely proportional to volume

D. Pressure becomes $3\text{atm}$ because pressure is inversely proportional to volume

Q.5. A block is placed on a rough horizontal surface and a horizontal force just sufficient to start motion is applied. Which coefficient of friction does this force help you determine and why?

A. It cannot be related to any coefficient, because friction is unpredictable

B. Coefficient of kinetic friction, because the block starts sliding

C. Coefficient of static friction, because motion is about to start

D. Average of static and kinetic friction, because both act at that instant

Q.6. Which of the following aqueous solutions will have the lowest freezing point, assuming complete dissociation of solutes?

A. $0.1{\text{mol L}}^{-1}$ NaCl

B. $0.1{\text{mol L}}^{-1}$ glucose

C. $0.1{\text{mol L}}^{-1}$ CaCl${}_2$

D. $0.1{\text{mol L}}^{-1}$ urea

Q.7. Which of the following correctly matches a human endocrine gland with a hormone it secretes and the primary effect of that hormone?

A. Pancreatic beta cells – glucagon – increases blood glucose

B. Anterior pituitary – oxytocin – stimulates milk ejection

C. Adrenal medulla – cortisol – lowers blood glucose

D. Thyroid gland – thyroxine – increases basal metabolic rate

Q.8. In a photoelectric effect experiment, light of frequency just above the threshold frequency is incident on a metal surface. If the intensity of light is doubled while keeping the frequency constant, what change is observed in the emitted photoelectrons?

A. Both maximum kinetic energy and number of photoelectrons emitted per second double

B. Maximum kinetic energy remains the same, number of photoelectrons emitted per second increases

C. Maximum kinetic energy becomes zero because electrons cannot escape at higher intensity

D. Maximum kinetic energy doubles, number of photoelectrons emitted per second remains the same

Q.9. In a patient, the blood plasma becomes hypotonic compared to the red blood cells. What will most likely happen to the red blood cells, and why?

A. They will remain unchanged because cell membranes prevent water movement

B. They will swell and may burst because water moves in by osmosis

C. They will shrink because water moves out by osmosis

D. They will first shrink then swell as ions move, but cell volume remains constant

Q.10. In an ecological experiment, a grassland is fertilized with excess nitrogen and phosphorus. Over several years, species richness of native grasses declines while a few fast-growing species dominate. Which concept best explains this outcome?

A. Resource partitioning

B. Competitive exclusion principle

C. Ecological succession

D. Allelopathy

Q.11. A point object is placed at a distance less than the focal length in front of a thin convex lens in air. If the surrounding medium is gradually changed to one whose refractive index approaches that of the lens material, what happens to the image?

A. The image disappears because the lens no longer forms any image

B. The virtual, erect, magnified image moves closer to the lens and becomes less magnified

C. The virtual, erect, magnified image moves farther from the lens and becomes more magnified

D. The image becomes real, inverted, and diminishes in size

Q.12. Which statement correctly differentiates simple diffusion from facilitated diffusion across the plasma membrane?

A. Simple diffusion can move substances against their concentration gradient, whereas facilitated diffusion cannot

B. Simple diffusion directly passes through the lipid bilayer, whereas facilitated diffusion requires specific membrane proteins

C. Facilitated diffusion is restricted to gases only, whereas simple diffusion transports ions

D. Facilitated diffusion requires ATP hydrolysis, whereas simple diffusion does not

Q.13. A block of mass $m$ is placed on a rough horizontal surface and a constant horizontal force $F$ is applied. The block just starts moving. Which frictional force acts at this instant, and what is its magnitude?

A. Kinetic friction, equal to $F$

B. Static friction, equal to ${\mu }_{k}N$

C. Kinetic friction, equal to ${\mu }_{s}N$

D. Static friction, equal to $F$

Q.14. An ideal cell of emf $E$ and negligible internal resistance is connected across a resistor $R$. Which statement correctly describes the power delivered to the resistor?

A. Power is $I^2\mathrm{/}E$, where $I=E\mathrm{/}R$

B. Power is $E\mathrm{/}R$ and independent of current

C. Power is $E^2\mathrm{/}I$, independent of resistance

D. Power is $EI$, where $I=E\mathrm{/}R$

Q.15. A ray of light is incident from air onto a glass slab at an angle $i$ less than the critical angle. Which of the following correctly describes the behaviour of the refracted ray inside the glass?

A. It bends away from the normal and travels faster

B. It bends towards the normal and travels slower

C. It bends along the surface with angle of refraction ${90}^{\circ }$

D. It undergoes total internal reflection at the first surface

Consistency is the silent engine of success in an exam as rigorous as NEET. By completing the Day 46 practice set, you have moved one step closer to mastering the intricacies of the this entrance syllabus. Don’t just check your scores, take the time to analyze your errors and revisit the corresponding NCERT sections for any questions that tripped you up today. Keep this disciplined pace, stay focused on your goal, and we will see you back here tomorrow for Day 47 to continue your climb toward a 650+ score.

ANSWERS & EXPLANATIONS

Ans.1. D. MgCl2 has stronger ionic bonds because ${\text{Mg}}^{2+}$ has a higher charge than ${\text{Na}}^{+}$. Melting point in ionic compounds is largely determined by lattice energy, which depends on the product of ionic charges and the distance between ions. ${\text{Mg}}^{2+}$ carries a $+2$ charge, and each ${\text{Cl}}^{-}$ carries a $-1$ charge, giving stronger Coulombic attraction than the $+1$ to $-1$ interactions in $\text{NaCl}$. Additionally, the smaller ionic radius of ${\text{Mg}}^{2+}$ compared to ${\text{Na}}^{+}$ reduces the distance between ions, further increasing attraction. 

Ans.2. B. 4s. The motion consists of two equal time intervals: one while going up and one while coming down. Time to reach maximum height is $t=v_0\mathrm{/}g=20\mathrm{/}10=2\text{s}$. After that, the ball falls back with the same magnitude of acceleration and covers the same vertical distance in the same time, taking another $2\text{s}$. Therefore, the total time of flight is $4\text{s}$. 

Ans.3. D. They synthesize proteins by translating messenger RNA. Ribosomes are ribonucleoprotein complexes composed of ribosomal RNA and proteins, found either free in the cytosol or bound to the rough endoplasmic reticulum. During translation, ribosomes read the sequence of codons on messenger RNA and, with the help of transfer RNA, link amino acids together in the correct order to form polypeptides. This process is central to gene expression because it converts genetic information encoded in nucleic acids into functional proteins. Some proteins made on free ribosomes remain in the cytosol, while those synthesized on bound ribosomes are often secreted, inserted into membranes, or targeted to organelles. 

Ans.4. D. Pressure becomes $3\text{atm}$ because pressure is inversely proportional to volume. For an ideal gas undergoing an isothermal process, Boyle’s law states $P_1{V}_1=P_2{V}_2$. Here, $P_1=1\text{atm}$, and the final volume is $V_2=V_1\mathrm{/}3$. Substituting into the equation gives $1\times V_1=P_2\times V_1\mathrm{/}3$, so $P_2=3\text{atm}$.

Ans.5. B. Coefficient of static friction, because motion is about to start. At the limiting case, static friction attains its maximum value and balances the applied force. Only when the applied force slightly exceeds this maximum does the block begin to move and kinetic friction takes over. Therefore, the threshold force directly corresponds to ${\mu }_{\text{s}}$ via $f_{\text{s,max}}={\mu }_{\text{s}}N$. 

Ans.6. B. C4 plants avoid photorespiration by concentrating CO${}_2$ around Rubisco. The C4 pathway’s main advantage is not the absence of Rubisco but the creation of a microenvironment where Rubisco sees high CO${}_2$ and low O${}_2$, minimizing its wasteful oxygenase activity. By first fixing CO${}_2$ into a four-carbon compound in mesophyll cells and then releasing it in bundle sheath cells, C4 plants effectively elevate CO${}_2$ levels around Rubisco. 

Ans.7. C. $0.1{\text{mol L}}^{-1}$ CaCl${}_2$. Freezing point depression is a colligative property that depends on the number of solute particles in solution, not their identity. For a non-electrolyte like glucose, each molecule stays intact, so $0.1{\text{mol L}}^{-1}$ gives $0.1{\text{mol L}}^{-1}$ particles. For NaCl, which dissociates into two ions (Na${}^{+}$ and Cl${}^{-}$), $0.1{\text{mol L}}^{-1}$ yields approximately $0.2{\text{mol L}}^{-1}$ particles. For CaCl${}_2$, dissociation gives three ions per formula unit (Ca${}^{2+}$ and two Cl${}^{-}$), so $0.1{\text{mol L}}^{-1}$produces about $0.3{\text{mol L}}^{-1}$ particles, the highest among the options, resulting in the greatest freezing point depression. Therefore, the CaCl${}_2$ solution will have the lowest freezing point.

Ans.8. D. Thyroid gland – thyroxine – increases basal metabolic rate. The thyroid gland, located in the neck, secretes thyroid hormones, primarily thyroxine (T${}_4$4) and triiodothyronine (T${}_3$3). These hormones increase the basal metabolic rate by stimulating oxygen consumption and heat production in most tissues. They enhance carbohydrate, fat, and protein metabolism, influence growth and development, and are crucial for normal functioning of many organs. 

Ans.9. B. Maximum kinetic energy remains the same, number of photoelectrons emitted per second increases. The threshold frequency corresponds to the minimum photon energy needed to overcome the work function. Once this condition is met, any further increase in intensity at the same frequency provides more photons, not higher-energy photons. Hence, more electrons can be liberated but each has the same possible maximum kinetic energy as before.

Ans.10. B. They will swell and may burst because water moves in by osmosis. In a hypotonic solution, the water potential outside the cell is higher than inside. Due to osmosis, water flows from higher to lower solute concentration, meaning it enters the cells. Red blood cells lack a rigid cell wall, so they cannot resist excessive influx of water. As water accumulates, the cell volume increases, the membrane stretches, and beyond a threshold, the cells undergo hemolysis (bursting). This principle is clinically important when administering intravenous fluids: hypotonic saline can cause hemolysis, whereas isotonic saline maintains cell integrity by keeping extracellular and intracellular osmolarity balanced.

Ans.11. C. The virtual, erect, magnified image moves farther from the lens and becomes more magnified. As $n_{\text{medium}}$ approaches $n_{\text{lens}}$, the lens maker’s term $(n_{\text{lens}}\mathrm{/}{n}_{\text{medium}}-1)$tends to zero, making $f$ very large but not infinite until equality is reached. During this approach, the lens still forms a virtual image whose distance increases in magnitude. Magnification $m=v\mathrm{/}u$ increases correspondingly. Only in the limiting case where refractive indices are exactly equal does the lens lose all focusing ability, behaving like a parallel plate of glass; then rays simply continue undeviated. However, up to that limit, the image continues to exist, moving farther away and becoming more magnified rather than disappearing suddenly.

Ans.12. B. Simple diffusion directly passes through the lipid bilayer, whereas facilitated diffusion requires specific membrane proteins. Small non‑polar molecules such as $O_2$ and $C{O}_2$diffuse directly through the phospholipid bilayer without protein help, driven solely by their concentration gradient. In contrast, polar molecules and ions, which cannot easily cross the hydrophobic core, require channel or carrier proteins that provide a hydrophilic pathway. Both processes are passive and saturable, but facilitated diffusion shows specificity and can be regulated via protein expression and gating.

Ans.13. D. Static friction, equal to $F$. As the applied force increases from zero, static friction grows correspondingly to prevent motion, staying equal in magnitude and opposite in direction to $F$. When $F$ becomes equal to ${\mu }_{s}N$, static friction reaches its maximum and the body is on the verge of motion. At this precise instant, friction is still static, and its magnitude equals the applied force $F$. Immediately after, when motion starts, the friction switches to kinetic with typically lower magnitude.

Ans.14. D. Power is $EI$, where $I=E\mathrm{/}R$. Since the internal resistance is negligible, the entire emf appears across the resistor, leading to current $I$. The product of voltage (here $E$) and current gives the rate at which electrical energy is transferred to the resistor per unit time, which is dissipated as heat. Substitution yields $P=E^2\mathrm{/}R$, clearly showing the dependence on circuit parameters.

Ans.15. B. It bends towards the normal and travels slower. The higher optical density of glass compared with air means that light’s speed is reduced and the ray bends towards the normal upon entering. This standard behaviour underlies phenomena such as apparent depth in water and the bending of light in lenses.