NEET UG 2026 Daily Practice Questions: Success in NEET UG 2026 is built on one simple habit of daily, focused practice. Every set of well-chosen MCQs strengthens your concepts, sharpens your accuracy, and trains your mind for the real exam environment. In Day 22 of our Daily Practice Questions Series, we bring you another carefully designed question set from Physics, Chemistry, and Biology to keep your preparation consistent and move you one step closer to the 650+ score goal.
PHYSICS
Q.1. A block of mass 2kg rests on a smooth horizontal surface. A horizontal force F(t)= 4t N acts on it, where t is in seconds. What is the speed of the block at t=3s ?
A.
B.
C.
D.
Q.2. A uniform rod of length L and mass M is pivoted at one end and held horizontally. It is then released from rest. What is its angular acceleration just after release about the pivot ?
A.
B.
C.
D.
Q.3. A thin lens of focal length +20cm is placed in contact with another thin lens of focal length −10cm. What is the effective focal length of the combination in contact ?
A. +6.7cm
B. −20cm
C. +10cm
D. +20cm
Q.4. An object is placed 15cm in front of a concave mirror of focal length 10cm. Where will the image be formed ?
A. 6cm in front of the mirror
B. 30cm behind the mirror
C. 6cm behind the mirror
D. 30cm in front of the mirror
Q.5. A projectile is fired with initial speed u at an angle θ above the horizontal. Neglecting air resistance, what is the time of flight of the projectile ?
A.
B.
C.
D.
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CHEMISTRY
Q.6. Which of the following organic compounds will show a positive Tollens’ test ?
A. (acetaldehyde)
B. C6H6 (benzene)
C. (acetone)
D. (ethanol)
Q.7. Which of the following aqueous solutions will have the lowest pH, assuming equal concentrations ?
A. HCl
B. NaCl
C.
D.
Q.8. Which compound will show geometrical isomerism (cis–trans) due to restricted rotation around a double bond ?
A.
B.
C.
D.
Q.9. A radioactive sample has an initial activity of 800Bq. After 2 hours, its activity becomes 200Bq. What is its half-life ?
A. 1h
B. 4h
C. 3h
D. 2h
Q.10. A gas expands isothermally and reversibly from volume to . Which expression correctly gives the work done by the gas ?
A.
B.
C.
D.
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BIOLOGY
Q.11. In human physiology, which event occurs during the absolute refractory period of a neuron’s action potential ?
A. Ligand-gated channels on the dendrites are opening
B. Voltage-gated channels are inactivated and cannot reopen immediately
C. Another action potential can be generated if a stronger-than-normal stimulus is applied
D. The membrane potential is at its most negative value (hyperpolarized)
Q.12. In a dihybrid cross between two pea plants with genotype , what is the expected phenotypic ratio in the F2 generation for seed shape (R = round, r = wrinkled) and seed color (Y = yellow, y = green) ?
A. 3 round yellow : wrinkled green
B.1 round yellow : wrinkled yellow : 1 wrinkled green
C. 9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green
D. 9 round : 3 wrinkled : 4 yellow
Q.13. Which plant hormone primarily promotes cell elongation in coleoptile and stem regions ?
A. Cytokinins such as kinetin
B. Auxins such as indole-3-acetic acid (IAA)
C. Ethylene
D. Abscisic acid (ABA)
Q.14. Which of the following processes in human excretory physiology is primarily responsible for maintaining blood pH within a narrow range ?
A. Glomerular filtration of plasma proteins
B. Secretion of ions in the proximal convoluted tubule
C. Passive reabsorption of urea in the loop of Henle
D. Reabsorption of and secretion of in the nephron
Q.15. In the human cardiac cycle, the ‘lubb’ sound is produced primarily due to which event ?
A. Ejection of blood from ventricles into the aorta and pulmonary artery
B. Closure of atrioventricular (AV) valves at the beginning of ventricular systole
C. Closure of semilunar valves at the beginning of ventricular diastole
D. Opening of AV valves during atrial systole
And that’s a wrap for Day 22! If you felt a little smarter, a little faster, or even slightly more confident after solving today’s questions, then you’re already winning the NEET game. We absolutely love reading your comments and messages; they truly keep us motivated to create better practice sets and work even harder for you every single day. So keep solving, keep commenting, and keep chasing that 650+ dream one day, we’ll all celebrate your name on the medical college list together.
Share Your Scores Below, Also if there are any feedbacks or suggestions do let us know!
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ANSWERS & EXPLANATIONS
Ans.1. A. 9m/s. At t=3s, the instantaneous force is F(3)=12N, giving an instantaneous acceleration of , but that is not the acceleration over the entire interval. Since a(t)=2t, the velocity must be obtained by integration: . Substituting gives
Ans.2. D. . Some students might incorrectly use , as if all the mass were concentrated at the end of the rod. For a uniform rod pivoted at one end, the correct moment of inertia is . Substituting this into with gives .
Ans.3. B. +20cm. For thin lenses in contact, the powers add: . Here, and . So, Thus, .
Ans.4. D. 30cm in front of the mirror. For a concave mirror with focal length 10cm, the center of curvature is at 20cm. Placing the object at 15cm situates it between the focus and the center of curvature, leading to a real, inverted, and magnified image beyond the center of curvature.
Ans.5. A. . At maximum height, the vertical velocity becomes zero, and the time to reach that point is . However, the projectile still has to fall back to the original level, taking an equal amount of time. Therefore, the full duration of motion from launch to landing is double that value, giving the expression for time of flight as .
Ans.6. A. (acetaldehyde). The Tollens’ test relies on the presence of an aldehyde functional group that can be oxidized under mild conditions. Benzene lacks this functional group and does not react with Tollens’ reagent, so no silver mirror forms.
Ans.7. A. HCl. The ionization equilibrium of acetic acid is with an acid dissociation constant much less than 1. Therefore, a significant fraction of acetic acid molecules remain unionized, leading to a lower concentration and a higher pH compared to a strong acid like at the same concentration.
Ans.8. A. . For cis–trans isomerism around a double bond, each carbon in the must bear two different groups. In , the terminal carbon has two hydrogens, violating this condition. As a result, there is only one arrangement in space, and no cis–trans isomers exist.
Ans.9. A. 1h. The activity has decreased from 800Bq to 200Bq in 2h. That is a drop by a factor of 4, which is equivalent to two successive halvings: . Hence, the sample completes two half-lives in 2h, so each half-life must be .
Ans.10. B. . In an isothermal process, the internal energy of an ideal gas does not change because it depends only on temperature.
Ans.11. B. Voltage-gated channels are inactivated and cannot reopen immediately. During the absolute refractory period, which follows the depolarization phase, many voltage-gated channels enter an inactivated state in which their inactivation gates are closed
Ans.12. C. 9 round yellow : round green : wrinkled yellow : wrinkled green. For two genes each showing complete dominance and independent assortment, the F2 phenotypes segregate into four categories in the 9:3:3:1 ratio.
Ans.13. B. Auxins such as indole-3-acetic acid (IAA). While ethylene affects many developmental processes, including senescence and abscission, it does not serve as the primary hormone promoting longitudinal cell elongation in coleoptiles.
Ans.14. D. Reabsorption of and secretion of in the nephron. Blood pH is tightly controlled by renal handling of bicarbonate and hydrogen ions.
Ans.15. B. Closure of atrioventricular (AV) valves at the beginning of ventricular systole. Although blood flow changes during ejection, it is the snapping shut of valves that produces the audible ‘lubb’ and ‘dubb’ sounds.
