NEET UG 2026 Daily Practice Questions To Score 650+ (DAY 24)

NEET UG 2026 Daily Practice Questions: Welcome to Day 24 of your journey toward the magical 650+ score in NEET UG 2026. Every single question you practice today is a small step closer to that white coat moment you’ve been dreaming about. So grab your notes, sharpen your focus, and let’s turn today’s practice into tomorrow’s rank. Remember – consistency beats stress, and smart revision beats last-minute panic.

Let’s begin!

PHYSICS

Q.1. A projectile is fired with an initial velocity making an angle $\theta$θ with the horizontal. Neglecting air resistance, which of the following changes will increase its time of flight without changing its maximum height?

A. Increase the initial speed and decrease the angle θ appropriately

B. Keep the horizontal component of velocity same and increase the vertical component

C. Keep the vertical component of velocity same and increase the horizontal component

D. Decrease the initial speed and increase the angle θ appropriately

Q.2. A wire of length L and resistance R is uniformly stretched so that its length becomes 2L. What happens to its resistance, assuming volume remains constant?

A. Resistance becomes 2R

B. Resistance becomes R\/2

C. Resistance remains R

D. Resistance becomes 4R

Q.3. Which of the following statements about electromagnetic waves is correct ?

A. Their speed in vacuum depends on their frequency

B. They carry energy but not momentum

C. Electric and magnetic fields are perpendicular to each other and to the direction of propagation

D. They require a material medium for propagation

Q.4. A current of 2A flows through a resistor of resistance 5Ω. What is the potential difference across the resistor?

A. 10V

B. 5V

C. 7.5V

D. 2.5V

Q.5. The refractive index of glass with respect to air is 1.5. If the speed of light in vacuum is $3.0\times {10}^8{\text{m s}}^{-1}$, what is the speed of light in glass?

A. $4.5\times {10}^8{\text{m s}}^{-1}$

B. $1.0\times {10}^8{\text{m s}}^{-1}$

C. $2.0\times {10}^8{\text{m s}}^{-1}$

D. $1.5\times {10}^8{\text{m s}}^{-1}$

CHEMISTRY

Q.6. When monochromatic light is incident on a metal surface, electrons are emitted. Which change will increase the maximum kinetic energy of photoelectrons?

A. Increase the duration of exposure

B. Increase the intensity of incident light

C. Increase the frequency of incident light

D. Increase the area of the metal surface

Q.7. Which of the following statements about chemical equilibrium is correct?

A. At equilibrium, the reaction stops completely

B. Equilibrium is possible only in closed systems and only for gaseous reactions

C. At equilibrium, the forward and reverse reaction rates are equal

D. At equilibrium, the concentrations of reactants and products are always equal

Q.8. A solution contains a weak acid HA and its salt NaA. Which of the following best explains why this solution resists changes in pH upon addition of small amounts of acid or base?

A. The salt suppresses the ionization of water completely

B. The solution has a very low concentration of ions

C. The weak acid and its conjugate base neutralize added acid or base

D. The solution has equal concentrations of ${\mathrm{H}}^{+}$ and $\mathrm{O}{\mathrm{H}}^{-}$

Q.9. Which statement best explains why group 1 metals are more reactive than group 2 metals in the same period?

A. Group 1 metals have lower nuclear charge than group 2 metals

B. Group 1 metals have higher ionization energy than group 2 metals

C. Group 1 metals lose two electrons more easily than group 2 metals

D. Group 1 metals need to lose only one electron to achieve a noble gas configuration

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Q.10. Which statement about coordination compounds is most accurate?

A. All ligands must be neutral molecules

B. The coordination number is the charge on the complex ion

C. In a complex, the central metal atom always has zero oxidation state

D. Ligands donate electron pairs to the central metal ion, forming coordinate bonds

BIOLOGY

Q.11. In human reproduction, which event is directly triggered by a surge of luteinizing hormone (LH) in the middle of the menstrual cycle?

A. Thickening of the endometrium

B. Implantation of the embryo in the uterus

C. Ovulation, i.e., release of the secondary oocyte from Graafian follicle

D. Formation of the morula

Q.12. Which of the following best describes linkage in genetics?

A. Tendency of genes to assort independently during gamete formation

B. Tendency of genes located close together on the same chromosome to be inherited together

C. Exchange of genetic material between non-homologous chromosomes

D. Random mutation of genes during meiosis

Q.13. A man with blood group A marries a woman with blood group B. Their child has blood group O. Which genotypes of the parents are consistent with this observation?

A. Father ${\mathrm{I}}^{\mathrm{A}}{\mathrm{I}}^{\mathrm{A}}$, mother ${\mathrm{I}}^{\mathrm{B}}{\mathrm{I}}^{\mathrm{B}}$

B. Father ${\mathrm{I}}^{\mathrm{A}}{\mathrm{I}}^{\mathrm{O}}$, mother ${\mathrm{I}}^{\mathrm{B}}{\mathrm{I}}^{\mathrm{O}}$

C. Father ${\mathrm{I}}^{\mathrm{A}}{\mathrm{I}}^{\mathrm{A}}$, mother ${\mathrm{I}}^{\mathrm{B}}{\mathrm{I}}^{\mathrm{O}}$

D. Father ${\mathrm{I}}^{\mathrm{A}}{\mathrm{I}}^{\mathrm{O}}$, mother ${\mathrm{I}}^{\mathrm{B}}{\mathrm{I}}^{\mathrm{B}}$

Q.14. Which of the following adaptations is most directly linked to efficient gas exchange in mammalian lungs?

A. Extensive network of capillaries around alveoli

B. Ciliated epithelium in the trachea

C. Presence of cartilage in bronchi

D. Thick alveolar walls

Q.15. A patient’s ECG shows no P waves but normal QRS complexes occurring at a regular rate of 40 beats per minute. Which part of the heart is most likely acting as the pacemaker?

A. Bundle of His

B. Atrioventricular (AV) node

C. Sinoatrial (SA) node

D. Purkinje fibers in the ventricular wall

And that’s a wrap for Day 24, champs!

If you showed up today and solved even a few questions with full focus, you’re already ahead of yesterday’s version of yourself, and that’s what real toppers do. Keep the momentum going, trust your preparation, and never forget why you started this journey. We truly love reading your comments and seeing your dedication; it keeps us motivated to work harder for you every single day. See you tomorrow for Day 25!

ANSWERS & EXPLANATIONS

Ans.1.B. Keep the horizontal component of velocity same and increase the vertical component. The time of flight T depends only on the vertical component $u\sin \theta$ according to $T=\frac{2u\sin \theta }{g}$ , while the horizontal component ucosθ only affects range.

Ans.2.D.  Resistance becomes 4R. Using $R=\rho \frac{L}{A}$ , if L→2L and A→A\/2, then $R^{\mathrm{\prime }}=\rho \frac{2L}{A\text{/}2}=4R$. This shows resistance is very sensitive to both length and cross-sectional area. In practice, making a conductor longer and thinner increases resistance significantly. 

Ans.3.C. Electric and magnetic fields are perpendicular to each other and to the direction of propagation.

Ans.4.A. 10V. Using Ohm’s law, V=IR , we multiply current and resistance. Substituting I=2A and R=5Ω, we get V=2×5=10V. A common mistake is to assume a direct equality between V and I when resistance is not 1Ω.

Ans.5.C. 2.0×108m/ s. The refractive index $n$n of a medium is defined as the ratio of the speed of light in vacuum $c$c to the speed of light in the medium $v$v: $n=\frac{c}{v}$. Rearranging this gives $v=\frac{c}{n}$. With n=1.5 and $c=3.0\times {10}^8{\text{m s}}^{-1}$, we get $v=\frac{3.0\times {10}^8}{1.5}=2.0\times {10}^8{\text{m s}}^{-1}$. 

Ans.6.C. Increase the frequency of incident light. According to Einstein’s photoelectric equation, Kmax=hν−ϕ , where $K_{\max }$ is maximum kinetic energy, h is Planck’s constant, ν is frequency, and ϕ is work function. Maximum kinetic energy depends directly on frequency, not intensity. Higher intensity at the same frequency simply means more photons and thus more emitted electrons, but each electron’s energy is unchanged.

Ans.7.C. At equilibrium, the forward and reverse reaction rates are equal. Whether in gas-phase reactions, saturated salt solutions, or heterogeneous equilibria involving solids, the key feature is equality of forward and reverse rates, leading to constant macroscopic properties.

Ans.8.C. The weak acid and its conjugate base neutralize added acid or base. In a buffer of weak acid $\mathrm{H}\mathrm{A}$ and salt $\mathrm{N}\mathrm{a}\mathrm{A}$, $\mathrm{H}\mathrm{A}$ can react with added base $\mathrm{O}{\mathrm{H}}^{-}$ to form ${\mathrm{A}}^{-}$ and water, while ${\mathrm{A}}^{-}$can react with added acid ${\mathrm{H}}^{+}$ to form $\mathrm{H}\mathrm{A}$. These reactions remove most of the added ${\mathrm{H}}^{+}$ or $\mathrm{O}{\mathrm{H}}^{-}$, so the pH changes only slightly. 

Ans.9.D. Group 1 metals need to lose only one electron to achieve a noble gas configuration. This one-step process of achieving stability makes reactions like formation of ionic compounds with halogens very easy. 

Ans.10.D.  Ligands donate electron pairs to the central metal ion, forming coordinate bonds. Understanding that ligands donate lone pairs clarifies many aspects of complex formation, including chelation, denticity, and the difference between inner and outer sphere complexes, all of which appear in NEET coordination chemistry.

Ans.11.C.  Ovulation, i.e., release of the secondary oocyte from Graafian follicle. LH acts on the ovary to trigger follicular rupture; later events like implantation depend on different hormonal balances including progesterone, which is secreted by the corpus luteum formed after ovulation.

Ans.12.B. Tendency of genes located close together on the same chromosome to be inherited together. This shows how physical arrangement of genes on chromosomes influences phenotypic ratios beyond simple Mendelian predictions, central to NEET-level understanding of chromosomal theory of inheritance.

Ans.13. B. Father ${\mathrm{I}}^{\mathrm{A}}{\mathrm{I}}^{\mathrm{O}}$, mother ${\mathrm{I}}^{\mathrm{B}}{\mathrm{I}}^{\mathrm{O}}$. This combination allows both parents to contribute ${\mathrm{I}}^{\mathrm{O}}$ alleles, giving a child with genotype ${\mathrm{I}}^{\mathrm{O}}{\mathrm{I}}^{\mathrm{O}}$ and blood group $\mathrm{O}$. Understanding these crosses is essential for solving NEET-level questions on inheritance of multiple alleles and codominance.

Ans.14.A. Extensive network of capillaries around alveoli. Gas exchange requires thin, well-perfused surfaces where blood and air meet. The dense capillary bed in the lungs maximizes this interface, allowing rapid equilibration of gases between alveolar air and blood, an idea repeatedly emphasized in NEET syllabus discussions of respiratory adaptations.

Ans.15.B. Atrioventricular (AV) node. When the SA node fails, the AV node often takes over as an ectopic pacemaker, generating impulses at a slower intrinsic rate of around 40-60 beats per minute. These impulses travel to the ventricles, producing normal-looking QRS complexes but no preceding P waves. This pattern points to a junctional rhythm originating near the AV node, an important concept in NEET cardiovascular physiology.

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