NEET UG Daily Practice Questions For 2026 to score 650+ (DAY 11)

NEET UG Daily Practice Questions For 2026: Consistency is the real game-changer in NEET UG preparation. With Day 11 of NEET UG Daily Practice Questions for 2026, aspirants get another focused opportunity to test concepts, improve accuracy, and build the problem-solving speed required to cross the 650+ score mark. Each question is curated to reflect NEET’s evolving trends and frequently tested topics.

PHYSICS

Q.1. A body is projected horizontally from the top of a smooth tower with an initial speed of u. Neglecting air resistance, which statement best describes the horizontal component of its velocity during the motion?

A. It remains constant because there is no horizontal force.

B. It increases uniformly because gravity has a horizontal component.

C. It becomes zero at the highest point of the trajectory.

D. It decreases uniformly due to gravity acting horizontally.

Q.2. A cylinder of mass M and radius R rolls without slipping on a horizontal surface. Its center of mass has speed v. What is the total kinetic energy of the cylinder?

A. $M{v}^2$

B. ${\displaystyle \frac{3}{4}}M{v}^2$

C. ${\displaystyle \frac{1}{4}}M{v}^2$

D. ${\displaystyle \frac{1}{2}}M{v}^2$

Q.3. A parallel-plate capacitor of capacitance C is connected to a battery of emf V. After it is fully charged, the battery is disconnected, and the distance between the plates is increased. What happens to the energy stored in the capacitor?

A. It remains the same because neither charge nor voltage changes.

B. It becomes zero because the battery is disconnected.

C. It increases because capacitance decreases while charge remains constant.

D. It decreases because capacitance increases while charge remains constant.

Q.4. In Young’s double-slit experiment, the fringe width is β when light of wavelength λ is used. If the entire apparatus is immersed in a medium of refractive index μ, what will be the new fringe width?

A. β/μ

B. μβ

C. $\beta \mathrm{/}{\mu }^2$

D. It remains β, independent of μ.

Q.5. Which statement correctly describes the relation between electric field $\vec{E}$ and electric potential V in electrostatics?

A. Electric field is always zero wherever electric potential is zero.

B. Electric potential is the cross product of electric field and displacement.

C. Electric field is the negative gradient of electric potential, E= -∇V.

D. Electric field and electric potential are always in the same direction..

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CHEMISTRY

Q.6. Which of the following changes will definitely increase the rate of a chemical reaction according to collision theory?

A. Decreasing the concentration of reactants in solution.

B. Increasing the surface area of a solid reactant by grinding it into fine powder.

C. Decreasing the temperature while keeping all other factors constant.

D. Adding an inert gas at constant volume to a gaseous reaction mixture.

Q.7. For a first-order reaction, which of the following statements is true about its half-life $t_{1\mathrm{/}2}$?

A. $t_{1\mathrm{/}2}$ is directly proportional to the initial concentration of the reactant.

B. $t_{1\mathrm{/}2}$is independent of the initial concentration of the reactant.

C. $t_{1\mathrm{/}2}$ is inversely proportional to the initial concentration of the reactant.

D. $t_{1\mathrm{/}2}$ decreases exponentially with time.

Q.8. Which of the following statements correctly describes hydrogen bonding in water?

A. Hydrogen bonding is purely covalent and does not involve any electrostatic attraction.

B. Hydrogen bonds form between a hydrogen atom covalently bonded to oxygen and a lone pair on another oxygen atom.

C. Hydrogen bonding can occur only within a single water molecule and not between different molecules.

D. Hydrogen bonding in water occurs between hydrogen and carbon atoms in different molecules.

Q.9. Which of the following statements best explains why graphite conducts electricity but diamond does not?

A. Both graphite and diamond have free electrons, but graphite has more impurities.

B. Graphite is metallic while diamond is ionic, so only graphite can conduct electricity.

C. Diamond has a layered structure with mobile electrons, whereas graphite has a rigid 3D network.

D. Graphite has delocalized $\pi$π-electrons that can move freely, while diamond has only localized σ-bonds.

Q.10. Which of the following best describes the Bohr model’s explanation for the line spectrum of hydrogen?

A. Electrons in a hydrogen atom can have any energy, leading to a continuous spectrum.

B. Electrons revolve in fixed orbits, and light is emitted when an electron jumps between these orbits, giving discrete spectral lines.

C. Electrons emit radiation continuously while moving in stable orbits, producing discrete lines.

D. Electrons remain stationary around the nucleus, and spectral lines arise from nuclear vibrations.

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BIOLOGY

Q.11. Which of the following statements about the human nephron is correct?

A. Glomerulus is a cup-shaped structure that collects urine from the nephron.

B. Ultrafiltration of blood occurs primarily in the loop of Henle.

C. The collecting duct is responsible only for filtering blood, not for water reabsorption.

D. Most reabsorption of glucose and amino acids occurs in the proximal convoluted tubule (PCT).

Q.12. Which combination of characteristics is typical for an amphibian like frog?

A. Pulmonary respiration only, dry scaly skin, external fertilization.

B. Gills throughout life, presence of lateral line system, external fertilization.

C. Cutaneous and pulmonary respiration, moist skin without scales, external fertilization.

D. Tracheal respiration, chitinous exoskeleton, internal fertilization.

Q.13. A plant shows wilting of leaves during midday, but the leaves regain turgidity by evening. Which of the following is the most appropriate explanation?

A. Transpiration rate is higher at midday than water absorption, causing temporary loss of turgor.

B. Root pressure is maximum at midday and minimum in the evening.

C. Photosynthesis stops at midday, so cells lose water and wilt.

D. Transpiration rate is very low at midday, leading to accumulation of water in leaves.

Q.14. Which of the following best describes the role of the sinoatrial (SA) node in the human heart?

A. It acts as the main contractile chamber that pumps blood to the lungs.

B. It is the pacemaker that initiates and regulates the heart’s rhythmic contractions.

C. It prevents backflow of blood between atria and ventricles.

D. It forms the thick muscular wall separating the two ventricles.

Q.15. Which law of inheritance is best illustrated when a cross between two heterozygous tall pea plants (Tt×Tt) produces both tall and dwarf offspring in a ratio of approximately 3:1?

A. Law of Dominance

B. Law of Independent Assortment

C. Law of Segregation

D. Law of Incomplete Dominance

Make these daily practice sessions a non-negotiable part of your routine. Attempt the questions with honesty, analyze mistakes carefully, and revise weak areas the same day. Small, disciplined efforts compound over time, bringing you closer to a confident performance and a high rank in NEET UG 2026.

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ANSWERS & EXPLANATIONS

Ans.1. A.  It remains constant because there is no horizontal force. In ideal projectile motion, the absence of horizontal forces means no horizontal acceleration.

Ans.2. B. ${\displaystyle \frac{3}{4}}M{v}^2$, For a solid cylinder rolling without slipping, total kinetic energy is the sum of translational and rotational energies.

Ans.3. C.  It increases because capacitance decreases while charge remains constant. The relationship $U={\displaystyle \frac{Q^2}{2C}}$ shows that for a fixed charge, decreasing the capacitance (by increasing plate separation) leads to a higher stored energy.

Ans.4. A. β/μ. In Young’s double-slit experiment, the fringe width β is given by $\beta ={\displaystyle \frac{D\lambda }{d}}$

Ans.5. C. Electric field is the negative gradient of electric potential, E= -∇V. This relation mathematically connects the vector field $\vec{E}$ to the scalar potential $V$and helps in calculating electric fields from known potentials.

Ans.6. B. Increasing the surface area of a solid reactant by grinding it into fine powder. When the surface area is increased, a larger portion of the solid reactant is exposed to other reactants, such as gases or solutions. This raises the number of available collision sites, thereby increasing the frequency of successful collisions that can overcome the activation energy barrier and form products.

Ans.7. B. $t_{1\mathrm{/}2}$is independent of the initial concentration of the reactant. For a first-order reaction, the half-life $t_{1\mathrm{/}2}$ is given by $t_{1\mathrm{/}2}={\displaystyle \frac{0.693}{k}}$, where k is the rate constant.

Ans.8. B. In water, each molecule has two O-H bonds, where hydrogen is covalently attached to a highly electronegative oxygen atom. This creates polar bonds, with hydrogen carrying a partial positive charge and oxygen a partial negative charge.

Ans.9. D. Graphite has delocalized π-electrons that can move freely, while diamond has only localized σ-bonds. 

Ans.10. B. Electrons revolve in fixed orbits, and light is emitted when an electron jumps between these orbits, giving discrete spectral lines. In the Bohr model of the hydrogen atom, electrons revolve around the nucleus in discrete allowed orbits, each with a specific energy. These orbits are called stationary states because electrons in them do not radiate energy despite undergoing centripetal acceleration.

Ans.11. D. Most reabsorption of glucose and amino acids occurs in the proximal convoluted tubule (PCT). The PCT has a brush border and abundant mitochondria, making it highly efficient in selective reabsorption of essential solutes such as glucose, amino acids, sodium ions, and a significant amount of water from the filtrate back into the blood.

Ans.12. C. Cutaneous and pulmonary respiration, moist skin without scales, external fertilization. This combination correctly summarizes key anatomical and physiological features of adult frogs and other amphibians.

Ans.13. A. Transpiration rate is higher at midday than water absorption, causing temporary loss of turgor. This imbalance between water loss and uptake explains why wilting can occur during the hottest part of the day and then reverse when environmental conditions improve.

Ans.14. B.  It is the pacemaker that initiates and regulates the heart’s rhythmic contractions. By generating regular electrical impulses, the SA node ensures coordinated atrial contractions and sets the overall pace for the cardiac cycle.

Ans.15. C. Law of Segregation. In a monohybrid cross with one gene pair, the Law of Segregation states that the two alleles in a heterozygous individual separate during gamete formation so that each gamete receives only one allele.

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