NEET UG Practice Questions Day 38

NEET UG Practice Questions Day 38: Preparing for the NEET UG exam requires consistent practice and a strong understanding of concepts. To help aspirants strengthen their preparation, we bring you Day 38, Practice Paper. This daily practice series is designed to help students revise important concepts from Physics, Chemistry, and Biology while improving their problem-solving speed and accuracy. Regular practice with exam-level questions not only boosts confidence but also helps students identify weak areas that need more attention.

PHYSICS

Q.1. Assertion: The specific charge for positive rays is a characteristic constant. 

Reason: The specific charge depends on charge and mass of positive ions present in positive rays

A. Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

B. Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

C. Assertion is correct but Reason is incorrect.

D. Both Assertion and Reason are incorrect.

Q.2. Assertion: Cathode rays produce fluorescence in glass and colour of glow depends on nature of glass. 

Reason: Cathode rays excite glass electrons and they on de-excitation emits radiation in visible region.

A. Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

B. Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

C. Assertion is correct but Reason is incorrect.

D. Assertion is incorrect but reason is correct.

Q.3. A circular loop of radius $R$ carries a steady current $I$ and lies in the plane of the page. A long straight wire, also carrying current $I$, is placed parallel to the plane of the loop, such that its axis passes through the center of the loop and is perpendicular to the plane of the loop. What is the net magnetic flux through the loop due to the magnetic field of the long straight wire?

A. Non-zero and equal to ${\mu }_{0}I\pi R^2\mathrm{/}(2\pi R)$

B. Non-zero and depends on the distance between the wire and the loop

C. Zero, because the magnetic field through different parts of the loop cancels out symmetrically

D. Zero, because the magnetic field lines from the straight wire are parallel to the plane of the loop at all points

Q.4. The kinetic energy of the photoelectrons increases by 0.62 $eV$ when the wavelength of incident light is changed from 500 $nm$ to another wavelength, which is approximately

A. 1250 $nm$

B. 1000 $nm$

C. 700 $nm$

D. 400 $nm$

Q.5. A radiation of energy $E$ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c is the velocity of light)

A. $EC$

B. ${\displaystyle \frac{E}{C}}$​

C. ${\displaystyle \frac{2E}{c}}$​

D. ${\displaystyle \frac{E}{c^2}}$​

CHEMISTRY

Q.6. A mixture of two or more ideal gases:

A. Does not follow the ideal gas equation

B. Does not follow the first law of thermodynamics

C. Has the same RMS speed (per molecule) for each gas

D. Has the same average translational kinetic energy foreach type of gas molecule

Q.7. A cavity is made within a solid, shaped in the form of a cube. The cavity is also cubical and centered within the solid. The temperature of the solid is raised. The volume of the cavity:

A. Increases by the same fraction as the cube

B. Increases by a lower fraction than the cube

C. Decreases

D. Remains the same

Q.8. Carbon and oxygen combine to form two oxides, carbon monoxide and carbon dioxide, in which the ratio of the weights of carbon and oxygen is respectively 12:16 and 12: 32. These figures illustrate the:

A. Law of constant proportions

B. Law of multiple proportions

C. Law of reciprocal proportions

D. Law of conservation of mass

Q.9. When two liquids A and B mix together, the boiling point of the solution is found to be higher than that of the individual liquids. The nature of the solution is:

1. Ideal solution.

2. Positive deviation with a non-ideal solution.

3. Negative deviation with a non-ideal solution.

4. Normal solution.

Q.10. A solution contains a weak monoprotic acid $HA$ with acid dissociation constant $K_a$. The initial concentration of $HA$ is C. Assuming $HA$ is only slightly dissociated, which expression BEST approximates the concentration of hydrogen ions $[H^{+}]$ at equilibrium?

A. $[H^{+}]=C$

B. $[H^{+}]\approx {\displaystyle \frac{C}{2}}$

C. $[H^{+}]=K_a$

D. $[H^{+}]\approx \sqrt{K_{a}C}$

Read Also: NEET UG Day 37 Free Practice Test

BIOLOGY

Q.11. You do not expect to see in a plant cell:

A. A centrosome

B. A tonoplast

C. An elaioplast

D. 80 S ribosomes

Q.12. Which of the following statements best explains why plant cells cannot undergo cytokinesis through cleavage furrow formation?

1. Plant cells lack centrioles, which are essential for cleavage furrow formation.

2. Plant cells have a rigid cell wall that prevents the plasma membrane from pinching inward.

3. Plant cells do not have actin and myosin filaments required for cleavage furrow formation.

4. Plant cells have a large central vacuole that interferes with cleavage furrow formation.

Q.13. All the following biomolecules can be called bothpolymers and macromolecules except:

A. Nucleic acids

B. Lipids

C. Proteins

D. Carbohydrates

Q.14. How can tissue culture be used to produce virus-free plants from infected plants?

1. By removing the infected leaves and growing them insterile conditions.

2. By isolating and growing the virus-free meristem from infected plants.

3. By using pesticides in the growth medium to kill the virus.

4. By exposing the infected plants to ultraviolet light to eliminate the virus.

Q.15. There can be a net gain of __ ATP moleculesduring aerobic respiration of one molecule of glucose [as per NCERT textbook]:

A. 40

B. 30

C. 36

D. 38

We hope these NEET UG Practice Questions – Day 38 helped you test your preparation and sharpen your concepts. Consistent practice is one of the most effective ways to improve your performance in the exam. If you are aiming for a 650+ score in NEET UG, make sure to practice daily and revise regularly. You can also download Edufever’s free study materials, notes, and practice resources from the link provided below to strengthen your preparation and move one step closer to your dream medical college.

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ANSWERS & EXPLANATIONS

Ans. 1. (B) The specific charge of a positive ion corresponding to one gas is fixed, but it is different for different gases. The specific charge depends on the charge and mass of the positive ions present in positive rays.

Ans.2. (A) Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

Ans. 3. (D) Zero, because the magnetic field lines from the straight wire are parallel to the plane of the loop at all points. Hence, there is no component of the magnetic field passing through the loop’s area.

Ans. 4. (D). 400 nm. In the photoelectric effect, the maximum kinetic energy $K_{\max }$ of photoelectrons is $K_{\max }=\frac{hc}{\lambda }-\varphi$, where $\varphi$ is the work function, $h$ is Planck’s constant, $c$ is the speed of light, and $\lambda$ is the wavelength.

Ans. 5. (C). The change in momentum of the radiation is $\mathrm{\Delta }p=-\frac{E}{c}-\frac{E}{c}=-\frac{2E}{c}$. By conservation of momentum, the surface gains an equal and opposite momentum, so the magnitude transferred to the surface is $\frac{2E}{c}$.

Ans. 6. (D). For an ideal gas, average translational kinetic energy per molecule is $\frac{3}{2}kT$ which depends only on temperature, not on the nature or mass of the gas. In a mixture at a single temperature, every species has the same average translational kinetic energy.

Ans. 7. (A).  increases by the same fraction as the cube. When the solid cube is heated, it undergoes uniform thermal expansion in all directions due to isotropic expansion. The cavity, being centered and cubical, expands exactly as if it were filled with the same solid material.

Ans.8. (B). The ratio of these oxygen masses is 16:32 or 1:2, which is a simple whole number ratio. This exactly matches the law of multiple proportions: when two elements form more than one compound, the masses of one element combining with a fixed mass of the other are in small whole number ratios.

Ans. 9. (C). Negative deviation with a non-ideal solution.

When two liquids mix and the solution’s boiling point is higher than that of either pure liquid, it shows stronger intermolecular forces in the solution than in the pure liquids. This results in negative deviation from Raoult’s law.

For negative deviation:

• Common examples: acetone-chloroform, nitric acid-water
• Vapor pressure of solution < ideal (predicted by Raoult’s law)
• Higher boiling point required to reach atmospheric pressure

Ans. 10. D. $[H^{+}]\approx \sqrt{K_{a}C}$. This approximation is valid when the degree of dissociation is small and correctly incorporates the dependence on both $K_a$ and $C$.

Ans. 11. A. A centrosome. Plant cells lack centrosomes, which organize microtubules during animal cell division; they use alternative structures like the nuclear envelope and phloem for spindle formation.

Ans. 12. B. The rigid cell wall surrounding plant cells prevents the plasma membrane from pinching inward to form a cleavage furrow, as this would require deformation that the wall resists.

Ans. 13. B. Lipids. Lipids are considered macromolecules due to their large size but are not true polymers, as they do not form by linking repeating monomeric units through covalent bonds like the others.

Ans .14. B. Meristems lack vascular connections where viruses spread via phloem, allowing culture of clean explants (0.1-0.5 mm) into virus-free plantlets under sterile conditions.

Ans.15.(C). 36. Glycolysis yields 2 ATP + 2 NADH (equivalent to 6 ATP).

Pyruvate to Acetyl CoA yields 2 NADH (6 ATP).

Krebs cycle yields 2 GTP (2 ATP) + 6 NADH (18 ATP) + 2 FADH₂ (4 ATP).

Total: 38 ATP theoretical, but 2 ATP cost for NADH shuttle reduces it to 36 ATP net.

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