Free NEET UG Practice Test Day 35

Free NEET UG Practice Test Day 35: Preparing for the NEET UG requires consistent practice, conceptual clarity, and regular self-assessment. To help you stay on track with your preparation, we bring you Day 35 practice set. These questions are designed according to the latest exam pattern and focus on strengthening your understanding of important concepts from Physics, Chemistry, and Biology. Solving a few quality questions every day not only improves accuracy but also builds the confidence needed to perform well in the actual exam.

BIOLOGY

Q.1. A patient is given a weak monoprotic acid drug orally. In the highly acidic environment of the stomach, the drug is largely unionized and lipid-soluble, while in the more alkaline small intestine it is largely ionized. Which of the following statements best explains where maximum absorption of this drug will occur and why?

A. Maximum absorption occurs in the small intestine because blood flow is low and transit time is short

B. Maximum absorption occurs in the small intestine because of its enormous surface area and permeable epithelium despite the drug being more ionized

C. Maximum absorption occurs in the stomach because the unionized form predominates and the surface area is high

D. Maximum absorption is equal in both stomach and small intestine because pH partitioning cancels out other factors

Q.2. An isolated skeletal muscle fibre is stimulated to contract isotonically against a series of different loads. Which of the following correctly describes the relationship between the load and both the velocity and duration of shortening?

A. As load increases, velocity of shortening increases and duration of shortening decreases

B. As load increases, velocity decreases but duration of shortening increases

C. Load does not affect velocity or duration of shortening in isotonic contraction

D. As load increases, both velocity and duration of shortening decrease

Q.3. In human physiology, which of the following best explains why the partial pressure of oxygen in the alveoli $(P_{\text{A}}{\text{O}}_2)$ is lower than that of inspired dry air, even when breathing room air at sea level?

A. Alveolar oxygen is higher because carbon dioxide is constantly exhaled from the blood

B. Alveolar oxygen is continually diluted by residual volume and water vapour, and oxygen is continuously taken up by blood

C. Alveolar oxygen is lower only during breath-holding and equals inspired oxygen otherwise

D. The partial pressure of oxygen in alveoli equals that of inspired air in steady state conditions

Q.4. A mutant Arabidopsis line shows normal pre-mRNA synthesis but drastically reduced levels of mature mRNA for many genes, with accumulation of intron-containing transcripts in the nucleus. Which specific class of molecules is most likely defective in this mutant?

A. Small nuclear RNAs forming the spliceosome

B. Aminoacyl-tRNA synthetases responsible for tRNA charging

C. RNA-dependent RNA polymerases involved in siRNA synthesis

D. General transcription factors binding to the TATA box

Q.5. In human physiology, which specific event directly triggers the rapid upstroke (phase 0) of the cardiac ventricular action potential?

A. Inactivation of $\mathrm{N}{\mathrm{a}}^{+}\text{–}{\mathrm{K}}^{+}$ pumps causing depolarization

B. Efflux of ${\mathrm{K}}^{+}$ through delayed rectifier channels repolarizing the membrane

C. Opening of slow voltage-gated $\mathrm{C}{\mathrm{a}}^{2+}$ channels leading to $\mathrm{C}{\mathrm{a}}^{2+}$ influx

D. Opening of fast voltage-gated $\mathrm{N}{\mathrm{a}}^{+}$ channels causing a swift influx of $\mathrm{N}{\mathrm{a}}^{+}$

PHYSICS

Q.6. A particle moves along the x-axis under a position-dependent force $F(x)=k{x}^2$ (with $k>0$). It is released from rest at $x=a>0$. Ignoring all non-conservative forces, which statement best describes the motion?

A. It oscillates about $x=0$ with simple harmonic motion.

B. It moves towards $x=0$ and passes through with non-uniform acceleration.

C. It accelerates towards $+\mathrm{\infty }$ with ever-increasing acceleration.

D. It moves towards $x=0$, momentarily comes to rest there, then remains at rest.

Q.7. A projectile is fired from ground level with speed $u$u at an angle $\theta$ above the horizontal in a region where gravitational acceleration decreases with height as $g(h)=g_0{\left({\displaystyle \frac{R}{R+h}}\right)}^2$, where $R$is Earth’s radius and $h$h is height above the surface. Neglect air resistance. Which statement is most accurate regarding the time of flight compared to the usual constant-g case?

A. The time of flight is always greater than ${\displaystyle \frac{2u\sin \theta }{g_0}}$

B. The time of flight may be greater or less than ${\displaystyle \frac{2u\sin \theta }{g_0}}$ depending on $\theta$

C. The time of flight is always less than ${\displaystyle \frac{2u\sin \theta }{g_0}}$

D. The time of flight is exactly ${\displaystyle \frac{2u\sin \theta }{g_0}}$

Q.8. A Carnot engine operates between a hot reservoir at temperature $T_H$ and a cold reservoir at $T_C$ $(T_H>T_C)$. It delivers work $W$ per cycle. A reversible refrigerator operates between the same two reservoirs and uses exactly the work $W$ delivered by the engine to transfer heat from the cold to the hot reservoir. What net effect occurs on the two reservoirs after many cycles?

A. The cold reservoir gains heat while the hot reservoir loses heat overall

B. There is no net heat transfer to either reservoir

C. The hot reservoir gains heat while the cold reservoir loses heat overall

D. Both reservoirs gain heat energy overall

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Q.9. A beam of monochromatic light of wavelength $\lambda$ in vacuum is incident normally on a thin film of refractive index $n$ and thickness $t$, surrounded by air. The film is on top of a perfectly reflecting metal surface. For destructive interference in the reflected light (minimum intensity), which condition on $t$ is correct?

A. $2nt=$

B. $2nt=m\lambda$

C. $2nt=$

D. $2nt=$

Q.10. A radioactive sample contains nuclei that decay via two independent processes with decay constants ${\lambda }_1$ and ${\lambda }_2$. The processes are indistinguishable experimentally. If the initial number of nuclei is $N_0$, what is the effective half-life $T_{1\mathrm{/}2}$ of the sample?

A. $T_{1\mathrm{/}2}={\displaystyle \frac{\ln 2}{{\lambda }_1}}+{\displaystyle \frac{\ln 2}{{\lambda }_2}}$

B. $T_{1\mathrm{/}2}={\displaystyle \frac{\ln 2}{{\lambda }_1-{\lambda }_2}}$

C. $T_{1\mathrm{/}2}={\displaystyle \frac{\ln 2}{{\lambda }_1{\lambda }_2}}$

D. $T_{1\mathrm{/}2}={\displaystyle \frac{\ln 2}{{\lambda }_1+{\lambda }_2}}$

CHEMISTRY

Q.11. A 0.1 M weak monoprotic acid $\text{HA}$ is 1% ionized at 25 ${}^{\circ }\text{C}$. If the temperature is increased such that the degree of ionization becomes 4% for the same initial concentration, which statement about the reaction enthalpy $\mathrm{\Delta }H$ of ionization is most consistent with this observation?

A. ΔH<0, the ionization is exothermic

B. The sign of $\mathrm{\Delta }H$ΔH cannot be inferred from this data

C. ΔH≈0, the ionization is thermoneutral

D. ΔH>0, the ionization is endothermic

Q.12. Which of the following reactions is most likely to be kinetically inhibited despite having a negative $\mathrm{\Delta }G$ under standard conditions?

A. Dissolution of $\text{NaCl}$NaCl in water

B. Mixing ${\text{AgNO}}_3$ and $\text{NaCl}$ solutions to form a precipitate

C. Combustion of glucose in air to form ${\text{CO}}_2$ and ${\text{H}}_2\text{O}$

D. Neutralization of $\text{HCl}$ with $\text{NaOH}$ in aqueous solution

Q.13. Which of the following best explains why $\text{Li}$ forms ${\text{Li}}_2{\text{CO}}_3$ that is thermally less stable compared to ${\text{Na}}_2{\text{CO}}_3$, but ${\text{Li}}_2{\text{CO}}_3$ is less soluble in water than ${\text{Na}}_2{\text{CO}}_3$?

A. ${\text{Li}}^{+}$ has lower polarizing power than ${\text{Na}}^{+}$

B. Na+ is smaller and more polarizing, making ${\text{Na}}_2{\text{CO}}_3$ more covalent

C. Carbonate ions prefer to bind larger cations like ${\text{Na}}^{+}$ more strongly than smaller ones like ${\text{Li}}^{+}$

D. ${\text{Li}}^{+}$is smaller and more polarizing, increasing covalent character and affecting both stability and solubility

Q.14. A first-order reaction has a half-life of 10 minutes at 300 K and 5 minutes at 310 K. Assuming the Arrhenius equation holds, which of the following is the best estimate of the activation energy $E_a$ in kJ mol${}^{-1}$?

A. 55 kJ mol${}^{-1}$

B. 10 kJ mol${}^{-1}$

C. 110 kJ mol${}^{-1}$

D. 35 kJ mol${}^{-1}$

Q.15. For the gas-phase equilibrium ${\text{PCl}}_5(g)\rightleftharpoons {\text{PCl}}_3(g)+{\text{Cl}}_2(g)$, initially only ${\text{PCl}}_5$ is present at pressure $P_0$ in a closed container at temperature $T$. At equilibrium, the degree of dissociation is $\alpha$. Which expression correctly gives the equilibrium constant $K_p$?

A. $K_p={\displaystyle \frac{P_0{\alpha }^2}{1-{\alpha }^2}}$

B. $K_p={\displaystyle \frac{P_0{\alpha }^2}{1-\alpha }}$

C. $K_p={\displaystyle \frac{P_0\alpha }{1-\alpha }}$

D. $K_p={\displaystyle \frac{P_0\alpha }{(1+\alpha )}}$

We encourage all aspirants to attempt today’s questions sincerely and analyze your performance after completing the test. Regular practice like this can make a significant difference in your preparation journey for NEET UG. Stay consistent, keep revising your concepts, and make these daily practice sessions a part of your routine. We will continue bringing more such practice tests to support your preparation, so keep visiting regularly and keep pushing yourself one step closer to your medical dream.

ANSWERS & EXPLANATIONS

Ans. 1. B. Maximum absorption occurs in the small intestine because of its enormous surface area and permeable epithelium despite the drug being more ionized. For most drugs, the small intestine is the dominant site for absorption because structural features like villi and microvilli magnify the effective surface area and facilitate diffusion, even when the ionization state is not ideal, overshadowing the contribution from the stomach.

Ans.2. D. As load increases, both velocity and duration of shortening decrease. At higher loads, the muscle takes longer to develop tension and spends more time near isometric conditions, which often reduces the total duration of actual shortening. Under very heavy loads approaching maximum, there may be little to no shortening at all, so the duration of shortening becomes minimal.

Ans.3. B.  Alveolar oxygen is continually diluted by residual volume and water vapour, and oxygen is continuously taken up by blood. These processes occur continuously with each breath and are responsible for maintaining alveolar $P{\text{O}}_2$at a lower level than inspired dry air.

Ans. 4. A. Small nuclear RNAs forming the spliceosome. The key issue described is the accumulation of intron-containing pre-mRNA in the nucleus, indicating a failure in the splicing step of post-transcriptional processing. snRNAs are essential for forming the catalytic core and recognition elements of the spliceosome. Without functional snRNAs, the cell cannot efficiently remove introns, so mature mRNA levels fall, even though transcription itself proceeds normally.

Ans.5. D. Opening of fast voltage-gated $\mathrm{N}{\mathrm{a}}^{+}$Na+ channels causing a swift influx of $\mathrm{N}{\mathrm{a}}^{+}$Na+. The key event that initiates the rapid upstroke in ventricular muscle cells is the transient, large inward $\mathrm{N}{\mathrm{a}}^{+}$Na+ current through these channels.

Ans. 6. B. It moves towards $x=0$ and passes through with non-uniform acceleration. As it moves toward $x=0$, it converts potential energy into kinetic energy according to the work–energy theorem, gaining speed. At $x=0$ the force becomes zero but the velocity is maximum, so it cannot stop there; it overshoots into negative $x$. Beyond $x=0$, the force still points in the $+x$ direction (since $x^2$ is positive), so it decelerates but keeps moving into the negative side until the kinetic energy drops to zero at some $x<0$, then it reverses. The trajectory is thus through $x=0$with non-uniform acceleration.

Ans.7. A. The time of flight is always greater than ${\displaystyle \frac{2u\sin \theta }{g_0}}$. For any angle $\theta$, the vertical motion is governed by an acceleration whose magnitude never exceeds $g_0$ and falls below it whenever the projectile is above the surface. This systematically increases the time required to reverse the vertical component of velocity. Thus, no choice of $\theta$ can undo this fundamental effect, so the time is invariably larger than the simple constant-g prediction.

Ans. 8. C. The hot reservoir gains heat while the cold reservoir loses heat overall. The Carnot engine’s role is to convert some of the heat it takes from the hot reservoir into work, and part of what is not converted is sent to the cold reservoir. The refrigerator then uses that same work to pump even more heat from cold to hot than the engine gave to the cold side. This imbalance between removal and addition to the cold reservoir ensures a net cooling of the cold side and a net warming of the hot side.

Ans. 9. A. $2nt=$ . This ensures that the phase difference due to extra path in the film is an odd multiple of $\pi$π in a situation with no net phase inversion between the two main reflected rays.

Ans.10. D. $T_{1\mathrm{/}2}={\displaystyle \frac{\ln 2}{{\lambda }_1+{\lambda }_2}}$. This illustrates why adding decay channels always reduces the half-life: a larger $\lambda$ leads to a shorter $T_{1\mathrm{/}2}$.

Ans.11. D. ΔH>0. For an endothermic reaction, the van ‘t Hoff relation predicts that the equilibrium constant increases with temperature. As temperature rises, the system absorbs heat and shifts toward the ionic products ${\text{H}}^{+}$ and ${\text{A}}^{-}$, causing a higher fraction of the acid to ionize. The pronounced increase in ionization percentage is strong evidence that heat favors ionization, consistent with a positive enthalpy change.

Ans .12. C. combustion of glucose in air, which, despite being thermodynamically favorable, proceeds very slowly without appropriate catalysts or ignition due to high activation energy.

Ans. 13. D. Li+ is smaller and more polarizing, leading to a more covalent ${\text{Li}}_2{\text{CO}}_3$, which is less soluble and more thermally unstable than the more ionic ${\text{Na}}_2{\text{CO}}_3$.

Ans.14. A.  55 kJ mol${}^{-1}$. Plugging the observed doubling of rate into the Arrhenius equation yields a moderate activation energy, not an extremely high one.

Ans. 15. B. answer is: $K_p={\displaystyle \frac{P_0{\alpha }^2}{1-\alpha }}$. Because $K_p$Kp is defined as ${\displaystyle \frac{P_{}{\text{PCl}}_3{P}_{}{\text{Cl}}_2}{P_{}}}$, both product partial pressures depend linearly on $\alpha$, giving a factor of ${\alpha }^2$ in the numerator.

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