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Daily Practice Questions For NEET UG 2026 to score 650+ (DAY 18)

With exam-oriented MCQs and smart practice, this daily series helps aspirants stay consistent and move steadily toward a 650+ score.

Daily Practice Questions For NEET UG 2026: Welcome to Day 18 of your NEET UG 2026 daily practice series – yes, the one that’s quietly pushing you closer to that magical 650+ score. Think of today’s questions as a mini workout for your brain: a little stretch of concepts, a few twists of tricky options, and that satisfying moment when things click. No overthinking, no panic, just smart practice, sharp focus, and one more solid step toward exam-day confidence.

Let’s get started:

PHYSICS

Q.1. A ball is thrown vertically upward with initial velocity u. Neglecting air resistance, which graph best represents the variation of its velocity vv with time tt during its entire flight until it returns to the thrower?

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A. A straight line with positive slope starting from uu and crossing time axis at maximum height

B. A straight line with negative slope, starting from uu, crossing the time axis at t=u/g and continuing symmetrically into negative velocities

C. A horizontal line parallel to time axis at v=u

D. A straight line with negative slope starting from uu and crossing velocity axis at maximum height

Q.2. An object of mass 2kg is moving with a velocity of 5m/s. A constant force acts on it in the direction of motion, and its velocity becomes 11m/s. The work done by the force on the object is:

A. 36J

B. 96J

C. 64J

D. 128J

Q.3. Which of the following options correctly represents the direction of induced current when a bar magnet is moved towards a closed conducting loop with its north pole facing the loop?

A. Current is induced such that the face of the loop towards the magnet behaves like a south pole

B. Current direction is arbitrary and independent of magnet’s motion

C. No current is induced because the loop’s resistance is finite

D. Current is induced such that the face of the loop towards the magnet behaves like a north pole

Q.4. In a transverse wave on a string described by y(x,t)=Asin(kxωt), which of the following quantities represents the wave speed?

A. A

B. ωk

C. ω

D. k

Q.5. If a concave mirror forms a real, inverted image of an object placed beyond the centre of curvature, where will the image be formed?

A. Between the pole and focus

B. At the centre of curvature

C. Between focus and centre of curvature

D. Beyond the centre of curvature

Read Also: NEET UG Daily Practice Questions For 2026 to score 650+ (DAY 17)

CHEMISTRY

Q.6. Which of the following best explains why ionic compounds generally have high melting and boiling points?

A. Their covalent bonds are highly directional

B. They form discrete molecules with intramolecular hydrogen bonding

C. They have strong electrostatic forces of attraction between oppositely charged ions in a lattice

D. They consist of molecules held together by weak van der Waals forces

Q.7. Which of the following pairs forms a conjugate acid–base pair according to Brønsted–Lowry concept?

A. NH3 and Na+

B. H2O and NaOH

C. NaOH and Na+

D. HCl and Cl

Q.8. A solution has [H+]=1×105M. What is the pH of this solution at 25C?

A. 9

B. 7

C. 3

D. 5

Q.9. Which of the following statements about enzymes is most accurate for NEET-level understanding?

A. Enzymes increase the activation energy of a reaction to speed it up

B. Enzymes change the equilibrium position of a reversible reaction

C. Enzymes are consumed in the reaction and must be continuously synthesized

D. Enzymes lower the activation energy and are highly specific to their substrates

Q.10. The half-life of a radioactive substance is 10days. The time taken for its activity to become 116 of the initial value is:

A. 20 days

B. 30 days

C. 160 days

D. 40 days

BIOLOGY

Q.11. A pure-breeding tall pea plant (TT) is crossed with a pure-breeding dwarf pea plant (tt). The F1 plants are all tall. When two F1 plants are self-crossed, what phenotypic ratio is expected in the F2 generation?

A. All tall

B. 2 tall : 1 dwarf

C. 1 tall : 1 dwarf

D. 3 tall : 1 dwarf

Q.12. In human blood groups, the IA and IB alleles are codominant and both are dominant over i. Which of the following crosses can produce a child with blood group O?

A. IAIB × ii

B. IAi × IBi

C. IAIA × IBIB

D. IAIB × IAIA

Q.13. Which of the following is the best example of adaptive radiation as per NEET-level evolution syllabus?

A. Appearance of antibiotic resistance in a bacterial population

B. Development of similar-looking wings in butterflies and birds

C. Temporary physiological adjustments to high altitude in humans

D. Divergence of Darwin’s finches on the Galápagos Islands

Q.14. A cell in which the number of chromosomes is not an exact multiple of the haploid set is best described as:

A. Diploid

B. Polyploid

C. Haploid

D. Aneuploid

Read Also: Most Important Biology Diagram For NEET UG 2026 (Day 3)

Q.15. In the loop of Henle of a nephron, maximum reabsorption of water from the filtrate occurs in which segment under the influence of antidiuretic hormone (ADH)?

A. No part of loop of Henle is affected by ADH

B. Both limbs equally

C. Descending limb

D. Ascending limb

And that’s a wrap on Day 18! Every question you solved today added a tiny but powerful upgrade to your NEET readiness- because consistency wins every single time. Review your mistakes, celebrate your correct answers, and trust the process. You’re not just practicing questions; you’re training your mind to think like a NEET topper.

ANSWERS & EXPLANATIONS

Ans.1. B. A straight line with negative slope, starting from uu, crossing the time axis at t=u/g, and continuing symmetrically into negative velocities. The linear decrease in velocity is a direct consequence of uniform acceleration due to gravity. 

Ans.2. B. 96J. Initially, kinetic energy K1=12×2×52=25J. Finally, K2=12×2×112=121J. So, the work done W=K2K1=12125=96J. This illustrates the work-energy theorem: when a net force does work on an object, the object’s kinetic energy changes by exactly that amount.

Ans.3. A. Current is induced such that the face of the loop towards the magnet behaves like a south pole. As the north pole moves closer, flux through the loop increases, and induced current flows in such a direction that the resulting magnetic field opposes this increase. 

Ans.4. B.
ω
k
. For a sinusoidal wave of the form y(x,t)=Asin(kxωt), the wave speed v is given by the relation v=ωk. Here, klll is the wave number and ωω is the angular frequency.

Ans.5. C. Between focus and centre of curvature. This is one of the fundamental object-image position pairs for concave mirrors that students must memorize and understand via ray diagrams.

Ans. 6. C.  They have strong electrostatic forces of attraction between oppositely charged ions in a lattice. The entire crystal is held together by these ionic bonds, which require substantial energy input to break, leading to high melting and boiling points in ionic compounds.

Ans.7. D. HCl and Cl. These species differ only in the presence or absence of a proton, which fits the Brønsted- Lowry definition of a conjugate acid-base pair.

Ans.8. D.  Using the definition pH=log[H+], substitute [H+]=1×105. Since log(1×105)=5, we get pH=(5)=5

Ans.9. D. Enzymes lower the activation energy and are highly specific to their substrates. By lowering the activation energy barrier, enzymes allow more reactant molecules to reach the transition state at a given temperature, increasing reaction rate without being consumed. Their active sites are shaped so that only specific substrate molecules can bind effectively, which explains the lock-and-key or induced fit models commonly taught at NEET level.

Ans.10. D. 40 days. We need four half-lives because (12)4=116 . Multiplying the number of half-lives by the duration of one half-life, we get t=4×10=40days.

Ans.11. D. 3 tall: 1 dwarf. TT and Tt genotypes express the tall phenotype, while tt expresses the dwarf phenotype.

Ans.12. B. IAi × IBi. This is the only option where both parents carry the recessive i allele, allowing the combination ii in some offspring and hence the possibility of a child with blood group O.

Ans.13. D. Divergence of Darwin’s finches on the Galápagos Islands. Here, one ancestral finch species gave rise to multiple descendant species with specialized beaks and feeding strategies, occupying varied niches. This branching pattern of speciation and adaptation is what defines adaptive radiation.

Ans.14. D. Aneuploid. In aneuploidy, individual chromosomes are gained or lost, giving chromosome counts like 2n + 1 (trisomy) or 2n – 1 (monosomy).

Ans.15. A. Ascending limb is not where water is reabsorbed; in fact, it is largely impermeable to water, and ADH mainly acts on distal parts of the nephron, not on the ascent of the loop. However, among the given choices, the question specifically focuses on maximum water reabsorption under the influence of ADH, which actually occurs beyond the loop, in the collecting duct. 

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Prakriti Edufever Author

Prakriti Suman is a Research Associate at RM Group of Education, specialized in higher education research, academic analysis, and data-driven insights for student guidance and institutional strategy. She is an UGC NET Qualified Researcher with an interdisciplinary background in Forensic Science, Criminology, and Information Security, she brings a strong analytical perspective to understanding student behavior, academic trends, child psychology and professional education pathways.

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